BFMracing
General Category => General Board => Homework Haven => Topic started by: BFM_MiG on September 07, 2008, 05:36:54 PM
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im in Chem 2 (its a college prep course, and im not going to college to stuff anything with Chemistry lol)
well i need help in chemistry already (only a week and a half into the new school year)
here is my first one i dont remember/ understand:
1.) Calculate the mass of FeCl3 needed to prepare 250.0 mL of an aqueous FeCl3 solution that is 0.2500 Molarity in Cl- ion?
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Hey MiG,
I took Chemistry last year, so I might have forgotten some stuff, but let me try and help you.
1) Convert 250 ml to L; It will be 0.25 L
2) Molarity is mol of solute / L of solution, so write that out.
3) There are 3 Cl- required to make FeCl3, so 3 mol of Cl- is 1 mol of FeCl3
4) Use the period table to find the mass of FeCl3, and write that out.
5) Multiply and find your answer.
0.25 L FeCl3 0.25 mol Cl- 1 mol FeCl3 162.35 g FeCl3
x --------------- x ---------------- x --------------------- = 3.3823 g FeCl3
1 L FeCl3 3 mol Cl- 1 mol FeCl3
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thanks Rypto, i checked and your right! ill be posting in this ALOT! alot! i mean alot!
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I'm taking AP Chem this year, so I'll help out too :yesyes:
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i have to do a chem report today, so im sure i'll be posting alot of questions!!!
1000th post lol :drool:
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I'll get Mrs. Booyah to look at this thread. She is a Chemist.....so yea....I think she can help. :winkgrin:
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im dropping the class. if i dont then i wont have special Senior privileges and i have enough science credits (plus it will bring my cumulative AVG down as well which is at 3.7 for my whole High School Career :P)