BFMracing

General Category => General Board => Homework Haven => Topic started by: -shiNe! on August 19, 2011, 11:19:49 AM

Title: Quick Algebraic Q
Post by: -shiNe! on August 19, 2011, 11:19:49 AM

c to the power of -4 x c to the power of 0 Is Zero right?
Or maybe the answer would be c to the power of -4 since c to the power of 0 would be 1.

Hmm

Title: Re: Quick Algebraic Q
Post by: Zeek on August 19, 2011, 12:34:47 PM

if i remember correctly if the power is 0 then it is zero.

Title: Re: Quick Algebraic Q
Post by: BFM_Fénix on August 19, 2011, 12:45:27 PM

Quote from: ØRiK on August 19, 2011, 11:19:49 AM

c to the power of -4 x c to the power of 0 Is Zero right?
Or maybe the answer would be c to the power of -4 since c to the power of 0 would be 1.

Hmm

Ok, I don't really understand well your typing :P

If you mean:
(c^-4)(c^0)            *Being ^ equivalent to "to the power"
Then it is as you said in the text with the same color.

Remember that ALL powers give you magnitudes higher than 0 (it means that if you check the Absolute Value of your result, it will be always > 0)

Title: Re: Quick Algebraic Q
Post by: jim360 on August 19, 2011, 01:29:03 PM

Laws of powers:

x^a*x^b = x^a+b and x^a/x^b = x^a-b

"multiply, add; divide, subtract."

This also shows that x⁰ has to be 1, since x^a*x⁰ = x^a+0 = x^a .

Hope that answers the question fully.

Title: Re: Quick Algebraic Q
Post by: -shiNe! on August 19, 2011, 03:31:29 PM

Unfortunately I had to figure this one out on my own since It was needed asap. Luckily though I picked the right answer, as explained by Fenix first. But nonetheless, I took a guess on It and now yall have provided me with future knowledge. Thanks!

Title: Re: Quick Algebraic Q
Post by: BFM_Fénix on August 19, 2011, 11:08:52 PM

Quote from: BFM_three60 on August 19, 2011, 01:29:03 PM

Laws of powers:

x^a*x^b = x^a+b and x^a/x^b = x^a-b

"multiply, add; divide, subtract."

This also shows that x⁰ has to be 1, since x^a*x⁰ = x^a+0 = x^a .

Hope that answers the question fully.

Also note that:
(x^a)^b = x^a*b and b-root(x^a) = x^a/b

Hope all these simple laws of powers help you in future assignments. :D

Title: Re: Quick Algebraic Q
Post by: BFM_Edison on August 19, 2011, 11:25:35 PM

What field are we working in 0:)

Title: Re: Quick Algebraic Q
Post by: raiden2000 on October 22, 2011, 02:13:51 AM

looking back thru this forum...saw all these algebra problems...i'm in calc 3...so this is fun

anything raised to teh 0 power is one, therefore:

(c^-4)(c^0)

(c^-4)(1)

c^-4