Solving the quadratic equation 3y2+22y-18=0 gives y1 = (-22+ (484+216)1/2)/6 = (-22 + 7001/2)/6
Then y2 = (-22 - 7001/2)/6. That seems right.
Numerically these are roughly: y1=0.7429 and y2=-8.07625.
SO to answer your question, 3y2+22y-18= (y-0.7429)(y+8.07625)